What is the limit as x approaches 3 of (3+x)/(x^2-9) ?

The limit as x approaches 3 of (3+x)/(x^2-9) is diverges

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limit as x approaches 3 of (3+x)/(x^2-9)

x \to 3 lim (\frac{3 + x}{x ^{2} - 9})

diverges

Solution steps

x \to 3 lim (\frac{3 + x}{x ^{2} - 9})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to 3 + lim (\frac{3 + x}{x ^{2} - 9}) = \infty

x \to 3 - lim (\frac{3 + x}{x ^{2} - 9}) = - \infty

= diverges

x \to - 1 lim (4 x^{2} - 5 x)

x \to 0 - lim (x^{\frac{1}{2}})

x \to - π lim (cos (2 x))

x \to 3 lim (4 - x^{2})

t \to 0 lim (t^{3})

What is the limit as x approaches 3 of (3+x)/(x^2-9) ?
The limit as x approaches 3 of (3+x)/(x^2-9) is diverges