What is the derivative of 2^y+1 ?

The derivative of 2^y+1 is ln(2)*2^y

What is the first derivative of 2^y+1 ?

The first derivative of 2^y+1 is ln(2)*2^y

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derivative of

2^{y} + 1

ln (2) \cdot 2^{y}

Solution steps

\frac{d}{d y} (2^{y} + 1)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (2^{y}) + \frac{d}{d y} (1)

\frac{d}{d y} (2^{y}) = 2^{y} ln (2)

\frac{d}{d y} (1) = 0

= 2^{y} ln (2) + 0

Simplify

= ln (2) \cdot 2^{y}

\frac{3}{x ^{4}}

\frac{d}{d t} (5 t + 16 t^{2})

\frac{d}{d t} (- 80 - 12 + 2 t^{2})

x (1 + x)^{2}

\frac{( 3 x ^{4} + 9 x ^{2} + 1 )}{x}

What is the derivative of 2^y+1 ?
The derivative of 2^y+1 is ln(2)*2^y
What is the first derivative of 2^y+1 ?
The first derivative of 2^y+1 is ln(2)*2^y