derivative log_{10}(x)x+1

Lösung

ableitung von

lo g_{10} (x) x + 1

lo g_{10} (x) + \frac{1}{ln ( 10 )}

Schritte zur Lösung

\frac{d}{d x} (lo g_{10} (x) x + 1)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (lo g_{10} (x) x) + \frac{d}{d x} (1)

\frac{d}{d x} (lo g_{10} (x) x) = \frac{1}{ln ( 10 )} + lo g_{10} (x)

\frac{d}{d x} (1) = 0

= \frac{1}{ln ( 10 )} + lo g_{10} (x) + 0

Vereinfache

= lo g_{10} (x) + \frac{1}{ln ( 10 )}

d er i v a t i v e e^{- 3 x} sin (5 x)

\frac{d}{d x} ((\frac{x + 1}{x})^{\frac{3}{7}})

d er i v a t i v e y = \frac{arcsin ( 1 )}{x}

d er i v a t i v e \frac{( 1 - x ) x ^{2}}{( 1 + x ^{2} )}

d er i v a t i v e y = \frac{x}{( x ^{2} - 3 )}