integral x/((x+2))

Lösung

integral

\frac{x}{( x + 2 )}

x + 2 - 2 ln ∣ x + 2 ∣ + C

Schritte zur Lösung

\int \frac{x}{x + 2} d x

Wende U-Substitution an

= \int \frac{u - 2}{u} d u

Multipliziere aus

\frac{u - 2}{u} : 1 - \frac{2}{u}

= \int 1 - \frac{2}{u} d u

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d u - \int \frac{2}{u} d u

\int 1 d u = u

\int \frac{2}{u} d u = 2 ln ∣ u ∣

= u - 2 ln ∣ u ∣

Setze in

u = x + 2

ein

= x + 2 - 2 ln ∣ x + 2 ∣

Füge eine Konstante zur Lösung hinzu

= x + 2 - 2 ln ∣ x + 2 ∣ + C

in t e g r a l (e^{- t})^{2}

in t e g r a l 2 x (x^{2} + 1)^{\frac{1}{2}}

in t e g r a l \frac{1}{- x}

in t e g r a l \frac{( y + 1 )}{( y - 1 )}

in t e g r a l (- 1)^{x}