What is the integral of (x^2+4)/(x^2+4) ?

The integral of (x^2+4)/(x^2+4) is x+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of (x^2+4)/(x^2+4)

\int \frac{x ^{2} + 4}{x ^{2} + 4} d x

x + C

Solution steps

\int \frac{x ^{2} + 4}{x ^{2} + 4} d x

Simplify

= \int 1 d x

Integral of a constant:

\int a d x = a x

= 1 \cdot x

Simplify

= x

Add a constant to the solution

= x + C

\int y sinh (\frac{y}{a}) d y

\int \frac{1}{x} ((2 x^{2} - 3 x)^{2} + 4) d x

\int 4 x^{3} - 12 x y^{2} d y

\int \frac{x ^{2} - 4 x + 4}{x ^{2} - 4 x + 29} d x

\int (x^{2} + y^{2})^{\frac{- 3}{2}} d x

What is the integral of (x^2+4)/(x^2+4) ?
The integral of (x^2+4)/(x^2+4) is x+C