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人気のある微分積分 >

integral from 1 to e^2 of ln(2x)

解

\int_{1}^{e^{2}} ln (2 x) d x

解

e^{2} ln (2) + e^{2} - ln (2) + 1

+1

十進法表記

12.81761 \dots

解答ステップ

\int_{1}^{e^{2}} ln (2 x) d x

部分積分を適用する

= [x ln (2 x) - \int 1 d x]_{1}^{e^{2}}

\int 1 d x = x

= [x ln (2 x) - x]_{1}^{e^{2}}

限度を計算する:

e^{2} ln (2) + e^{2} - ln (2) + 1

= e^{2} ln (2) + e^{2} - ln (2) + 1

グラフ

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