integral from-infinity to 0 of 4^r

Lösung

\int_{- \infty}^{0} 4^{r} d r

\frac{1}{2 ln ( 2 )}

Dezimale

0.72134 \dots

Schritte zur Lösung

\int_{- \infty}^{0} 4^{r} d r

Berechne das unbestimmte Integral:

\int 4^{r} d r = \frac{2 ^{2 r - 1}}{ln ( 2 )} + C

Berechne die Grenzen:

\int_{- \infty}^{0} 4^{r} d r = \frac{1}{2 ln ( 2 )} - 0

= \frac{1}{2 ln ( 2 )} - 0

Vereinfache

= \frac{1}{2 ln ( 2 )}

\int_{- 1}^{2} x^{2} (3 - 2 x) d x

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