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人気のある微分積分 >

integral from-infinity to 0 of 4^r

解

\int_{- \infty}^{0} 4^{r} d r

解

\frac{1}{2 ln ( 2 )}

+1

十進法表記

0.72134 \dots

解答ステップ

\int_{- \infty}^{0} 4^{r} d r

不定積分を計算する:

\int 4^{r} d r = \frac{2 ^{2 r - 1}}{ln ( 2 )} + C

限度を計算する:

\int_{- \infty}^{0} 4^{r} d r = \frac{1}{2 ln ( 2 )} - 0

= \frac{1}{2 ln ( 2 )} - 0

簡素化

= \frac{1}{2 ln ( 2 )}

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