integral from 0 to 1 of 1/y+sqrt(x)

Lösung

\int_{0}^{1} \frac{1}{y} + x d x

\frac{1}{y} + \frac{2}{3}

Schritte zur Lösung

\int_{0}^{1} \frac{1}{y} + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} \frac{1}{y} d x + \int_{0}^{1} x d x

\int_{0}^{1} \frac{1}{y} d x = \frac{1}{y}

\int_{0}^{1} x d x = \frac{2}{3}

= \frac{1}{y} + \frac{2}{3}

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