integral from 0 to 4 of (x/(1+x^4))

Lösung

\int_{0}^{4} (\frac{x}{1 + x ^{4}}) d x

\frac{1}{2} arctan (16)

Dezimale

0.75418 \dots

Schritte zur Lösung

\int_{0}^{4} \frac{x}{1 + x ^{4}} d x

Berechne das unbestimmte Integral:

\int \frac{x}{1 + x ^{4}} d x = \frac{1}{2} arctan (x^{2}) + C

Berechne die Grenzen:

\int_{0}^{4} (\frac{x}{1 + x ^{4}}) d x = \frac{1}{2} arctan (16) - 0

= \frac{1}{2} arctan (16) - 0

Vereinfache

= \frac{1}{2} arctan (16)

\int_{0}^{2} \frac{x}{( x - 1 ) ^{2} ( x + 1 )} d x

\int_{0}^{1} sin (y^{2}) y d y

\int_{o}^{t} t d t

\int_{1}^{2} (x^{2} - 2 x) d x

\int_{2}^{3} x^{2} - 6 x + 8 d x