integral from 1 to 2 of x^2-4

解答

\int_{1}^{2} x^{2} - 4 d x

- \frac{5}{3}

十进制

- 1.66666 \dots

求解步骤

\int_{1}^{2} x^{2} - 4 d x

使用积分加法定则:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{2} d x - \int_{1}^{2} 4 d x

\int_{1}^{2} x^{2} d x = \frac{7}{3}

\int_{1}^{2} 4 d x = 4

= \frac{7}{3} - 4

化简

\frac{7}{3} - 4 : - \frac{5}{3}

= - \frac{5}{3}

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