integral from 0 to 1 of (2^x-2)

Lösung

\int_{0}^{1} (2^{x} - 2) d x

\frac{1}{ln ( 2 )} - 2

Dezimale

- 0.55730 \dots

Schritte zur Lösung

\int_{0}^{1} 2^{x} - 2 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} 2^{x} d x - \int_{0}^{1} 2 d x

\int_{0}^{1} 2^{x} d x = \frac{1}{ln ( 2 )}

\int_{0}^{1} 2 d x = 2

= \frac{1}{ln ( 2 )} - 2

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