integral from 0 to 1 of x^4-1

Lösung

\int_{0}^{1} x^{4} - 1 d x

- \frac{4}{5}

Dezimale

- 0.8

Schritte zur Lösung

\int_{0}^{1} x^{4} - 1 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} x^{4} d x - \int_{0}^{1} 1 d x

\int_{0}^{1} x^{4} d x = \frac{1}{5}

\int_{0}^{1} 1 d x = 1

= \frac{1}{5} - 1

Vereinfache

\frac{1}{5} - 1 : - \frac{4}{5}

= - \frac{4}{5}

\int_{0.1}^{3} ln (x) d x

\int_{- 3}^{3} x^{5} d x

\int_{0}^{5} \frac{3}{5 - x} d x

\int_{0}^{1} \frac{2}{2 - r ^{2}} r d r

\int_{- 2}^{2} (x^{3} - x^{5}) d x