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人気のある微分積分 >

integral from 1 to 2 of xsqrt(x^2-2)

解

\int_{1}^{2} x x^{2} - 2 d x

解

\frac{2 2}{3} + i \frac{1}{3}

解答ステップ

\int_{1}^{2} x x^{2} - 2 d x

u置換積分法を適用する

= \int_{i}^{2} u^{2} d u

べき乗則を適用する

= [\frac{u ^{3}}{3}]_{i}^{2}

限度を計算する:

\frac{2 2}{3} + i \frac{1}{3}

= \frac{2 2}{3} + i \frac{1}{3}

人気の例

integral from 1 to x of ln(y)

\int_{1}^{x} ln (y) d y

integral from 0 to 1/2 of (cos(pix)-2^x)

\int_{0}^{\frac{1}{2}} (cos (π x) - 2^{x}) d x

integral from 0 to 1 of (e^t-e+1)^2

\int_{0}^{1} (e^{t} - e + 1)^{2} d t

integral from 0 to 1 of sqrt(1)

\int_{0}^{1} 1

integral from 1 to 2 of (2-6y^2)

\int_{1}^{2} (2 - 6 y^{2}) d y