4ydx+xdy=0

Lösung

4 y d x + x d y = 0

y = \frac{c _{1}}{x ^{4}}

Schritte zur Lösung

4 y d x + x d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x ^{4}}

y = \frac{c _{1}}{x ^{4}}

2 x y^{^{'}} = 4 - y^{2}

t \frac{d y}{d t} = 16 y

2 x e^{2 t} d t + (1 + e^{2 t}) d x = 0

x^{^{'}} + a x = 0

y^{^{'}} x ln (x) - y = 0