(x^2+1)dy+xy^2dx=0

Lösung

(x^{2} + 1) d y + x y^{2} d x = 0

y = - \frac{2}{- ln ( x ^{2} + 1 ) + c _{1}}

Schritte zur Lösung

(x^{2} + 1) d y + x y^{2} d x = 0

Solve separable ODE:

y = - \frac{2}{- ln ( x ^{2} + 1 ) + c _{1}}

y = - \frac{2}{- ln ( x ^{2} + 1 ) + c _{1}}

x + y \frac{d y}{d x} = 0

y^{^{'}} = (1 + y^{2}) cos (t)

x y^{2} y^{^{'}} = x + 10

\frac{d y}{d x} = \frac{3 e ^{x}}{y}

y^{2} y^{^{'}} = x - 2