y^'=(ln(x))/(xy)

Lösung

y^{^{'}} = \frac{ln ( x )}{x y}

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

Schritte zur Lösung

y^{'} (x) = \frac{ln ( x )}{x y}

Solve separable ODE:

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

y = ln^{2} (x) + c_{1}, y = - ln^{2} (x) + c_{1}

\frac{d y}{d x} = - \frac{1}{sin ( y )}, y (- 3) = \frac{π}{2}

\frac{d y}{d x} (- y cot (x)) = \frac{sin ( 2 x )}{2}

y^{^{'}} = \frac{x ^{2} + 7 x + 3}{y ^{2}}, y (0) = 3

y^{^{'}} + (x + 2) y = 0

(e^{y} + 1)^{2} e^{- y} d x + (e^{x} + 1)^{7} e^{- x} d y = 0