y^'=y-4

Lösung

y^{^{'}} = y - 4

y = e^{t + c_{1}} + 4

Schritte zur Lösung

y^{'} (t) = y - 4

Solve separable ODE:

y = e^{t + c_{1}} + 4

y = e^{t + c_{1}} + 4

(x^{4} + 1) y^{^{'}} + 2 x^{3} y = x^{3}

y^{^{'}} = 2 - 3 y

y^{^{'}} = 8 - y

x \frac{d y}{d x} = e^{4 y + x}, x > 0

y^{^{'}} = 3 y, y (1) = 5