(2y+3)dy=(x^2+6x)dx

Lösung

(2 y + 3) d y = (x^{2} + 6 x) d x

y = \frac{- 9 + 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}, y = \frac{- 9 - 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}

Schritte zur Lösung

(2 y + 3) d y = (x^{2} + 6 x) d x

Solve separable ODE:

y = \frac{- 9 + 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}, y = \frac{- 9 - 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}

y = \frac{- 9 + 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}, y = \frac{- 9 - 81 - 12 ( - c _{1} - 9 x ^{2} - x ^{3} )}{6}

\frac{d y}{d t} = 1 + t + y^{2} + t y^{2}

2 y + 3 + (2 x - 4) \frac{d y}{d x} = 0

(x - 1) (\frac{d y}{d x}) = (4 - y^{2})

3 x y^{^{'}} - 2 y = 0, y (0) = x^{\frac{2}{3}}

cot (x) (e - y + 1) d x = (1 + sin^{2} (x)) d y