y^'=14y+1

Lösung

y^{^{'}} = 14 y + 1

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

Schritte zur Lösung

y^{'} (t) = 14 y + 1

Solve separable ODE:

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

y = \frac{e ^{14 t + c_{1}}}{14} - \frac{1}{14}

(csc (y)) d x + (cos^{2} (x)) d y = 0

x - 1 \frac{d y}{d x} = \frac{x}{y}, y = 1, x = 2

x y^{^{'}} + 2 y = y^{2}

\frac{d y}{d x} = - (x y) 2

y^{^{'}} = \frac{x + 1}{e ^{2 y}}