y^'=(7x^2-1)/(7+9y)

Lösung

y^{^{'}} = \frac{7 x ^{2} - 1}{7 + 9 y}

y = \frac{- 7 + - 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49}{9}, y = - \frac{- 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49 + 7}{9}

Schritte zur Lösung

y^{'} (x) = \frac{7 x ^{2} - 1}{7 + 9 y}

Solve separable ODE:

y = \frac{- 7 + - 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49}{9}, y = - \frac{- 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49 + 7}{9}

y = \frac{- 7 + - 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49}{9}, y = - \frac{- 6 ( - 7 x ^{3} + 3 x - c _{1} ) + 49 + 7}{9}

\frac{d y}{d t} = e^{t + y}

x y^{^{'}} + y = 1

3 t \frac{d y}{d t} = y cos (t)

y^{^{'}} = 4 x y^{2}

\frac{d y}{d x} - 3 x^{2} y = 0