y^'=-10x^3e^y

Lösung

y^{^{'}} = - 10 x^{3} e^{y}

y = - ln (\frac{5 x ^{4}}{2} - c_{1})

Schritte zur Lösung

y^{'} (x) = - 10 x^{3} e^{y}

Solve separable ODE:

y = - ln (\frac{5 x ^{4}}{2} - c_{1})

y = - ln (\frac{5 x ^{4}}{2} - c_{1})

\frac{d y}{d x} + 9 x y = 4 x

35 v^{^{'}} = 2 - 0.2 v, v (0) = - 6

\frac{d y}{d x} y = 3 x^{3 x}

y^{^{'}} - y = - y^{2}

5 x + y y^{^{'}} = 0, y (2) = 5