de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

2y^'+y=0,y(0)=e^{(-x)/2}

Lösung

2 y^{^{'}} + y = 0, y (0) = e^{\frac{- x}{2}}

Lösung

y = e^{\frac{- x + c _{1}}{2}}

Schritte zur Lösung

2 y^{'} (x) + y = 0

Solve separable ODE:

y = e^{\frac{- x + c _{1}}{2}}

y = e^{\frac{- x + c _{1}}{2}}

Graph

Beliebte Beispiele

(dy)/(dx)=(x^2)/(x^2(3y^2+1)),y(1)=4

\frac{d y}{d x} = \frac{x ^{2}}{x ^{2} ( 3 y ^{2} + 1 )}, y (1) = 4

(dy)/(dx)=x^5y^2

\frac{d y}{d x} = x^{5} y^{2}

5 x y y^{^{'}} = 1

y^{^{'}} = \frac{2 y}{t - 1}

y^'=5t^3y^{1/5},y(0)=0

y^{^{'}} = 5 t^{3} y^{\frac{1}{5}}, y (0) = 0