(dy)/(dt)+y=yte^{t+2}

Lösung

\frac{d y}{d t} + y = y t e^{t + 2}

y = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

Schritte zur Lösung

\frac{d y}{d t} + y = y t e^{t + 2}

Solve separable ODE:

y = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

y = e^{e^{2} (e^{t} t - e^{t}) - t + c_{1}}

(y^{2} - y) d x + x d y = 0

y y^{^{'}} = x^{2} e^{2 x + 2 y} sin (3 x)

x \cdot \frac{d y}{d x} = 2 + 3 y

5 y d x = 3 x d y

\frac{d x}{d k} + a x (k) = b