(dy)/(dx)e^{x+y}-x=0

Lösung

\frac{d y}{d x} e^{x + y} - x = 0

y = ln (- x e^{- x} - e^{- x} + c_{1})

Schritte zur Lösung

\frac{d y}{d x} e^{x + y} - x = 0

Solve separable ODE:

y = ln (- x e^{- x} - e^{- x} + c_{1})

y = ln (- x e^{- x} - e^{- x} + c_{1})

x y^{^{'}} = 3 (y^{2} + y)

y^{^{'}} = x y, y (1) = 1

\frac{d v}{d t} + \frac{v}{3} = 4

\frac{5}{3} y + \frac{d y}{d x} = 3 - 5 y

y^{^{'}} = 4 y^{2} cos (x)