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Beliebt Rechnen >

d/(dθ)(r(θ))+r(θ)tan(θ)=tan(θ)

Lösung

\frac{d r}{d θ} + r tan (θ) = tan (θ)

Lösung

r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

Schritte zur Lösung

\frac{d}{d θ} (r θ) + r θ tan (θ) = tan (θ)

\frac{d}{d θ} (r θ) = r

r + r θ tan (θ) = tan (θ)

r + r θ tan (θ) = tan (θ) : r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

r = \frac{tan ( θ )}{1 + tan ( θ ) θ}; 1 + tan (x) x \neq = 0

Beliebte Beispiele

(dy)/(dx)=(1+x^2)/(1-y^2),y=0,x=0

\frac{d y}{d x} = \frac{1 + x ^{2}}{1 - y ^{2}}, y = 0, x = 0

f^'(x)+2xf(x)=0,f(0)=3

f^{^{'}} (x) + 2 x f (x) = 0, f (0) = 3

-2y(dy)/(dx)+x^2+2x^4=0

- 2 y \frac{d y}{d x} + x^{2} + 2 x^{4} = 0

4y(dy)/(dx)=x+xy^2

4 y \frac{d y}{d x} = x + x y^{2}

y^'sin(2y)-cos(x)=0

y^{^{'}} sin (2 y) - cos (x) = 0