4y(dy)/(dx)=x+xy^2

Lösung

4 y \frac{d y}{d x} = x + x y^{2}

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

Schritte zur Lösung

4 y \frac{d y}{d x} = x + x y^{2}

Solve separable ODE:

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

y = e^{\frac{x ^{2}}{4} + c_{1}} - 1, y = - e^{\frac{x ^{2}}{4} + c_{1}} - 1

y^{^{'}} sin (2 y) - cos (x) = 0

\frac{df}{d t} = f (t)

y^{^{'}} + ln (x) \cdot y = 3 \cdot ln (x)

\frac{d V}{d t} = 60 - \frac{1}{100} V

\frac{d x}{d t} - 5 x = 3