(3y^2-4x^{-1}y)dx+(3xy-4)dy=0

Lösung

(3 y^{2} - 4 x^{- 1} y) d x + (3 x y - 4) d y = 0

y = \frac{c _{1}}{x}

Schritte zur Lösung

(3 y^{2} - 4 x^{- 1} y) d x + (3 x y - 4) d y = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

x^{^{'}} = \frac{x ^{2}}{2}

y^{^{'}} = \frac{t}{y}, y (0) = 1

y^{^{'}} - 10 x y = 0

2 t y^{^{'}} = 6 y

y^{^{'}} = \frac{3 sin ( x )}{sin ( y )}, y (0) = \frac{π}{2}