de

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Beliebt Rechnen >

(x^2+1)(tan(y))y^'=x

Lösung

(x^{2} + 1) (tan (y)) y^{^{'}} = x

Lösung

y = arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn, y = - arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn

Schritte zur Lösung

(x^{2} + 1) (tan (y)) y^{'} (x) = x

Solve separable ODE:

y = arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn, y = - arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn

y = arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn, y = - arccos (\frac{c _{1} x ^{2} + 1}{x ^{2} + 1}) + 2 πn

Graph

Beliebte Beispiele

y^'=(1+4x)sqrt(y),y(0)=1

y^{^{'}} = (1 + 4 x) y, y (0) = 1

(x^{-2}y^{-5})dx+(x^{-3}y^{-4})dy=0

(x^{- 2} y^{- 5}) d x + (x^{- 3} y^{- 4}) d y = 0

(dV)/(dt)=20-8/100 V

\frac{d V}{d t} = 20 - \frac{8}{100} V

(dy)/(dt)=(2t)/(1+2y)

\frac{d y}{d t} = \frac{2 t}{1 + 2 y}

(dy)/(dx)+ytan(x)=0

\frac{d y}{d x} + y tan (x) = 0