y^'=(ln(x))/(xy^2)

Lösung

y^{^{'}} = \frac{ln ( x )}{x y ^{2}}

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

Schritte zur Lösung

y^{'} (x) = \frac{ln ( x )}{x y ^{2}}

Solve separable ODE:

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

y = 3 \frac{3 ln ^{2} ( x ) + c _{1}}{2}

y^{^{'}} + 4 y = 5

y^{^{'}} + 2 y = - 8

\frac{d y}{d x} = - \frac{3}{5} x^{7} y^{3}

\frac{d x}{d y} + 2 x y^{2} = 0

\frac{d v}{d x} = - 0.4 v