y^'=g-y

Lösung

y^{^{'}} = g - y

y = - e^{- t - c_{1}} + g

Schritte zur Lösung

y^{'} (t) = g - y

Solve separable ODE:

y = - e^{- t - c_{1}} + g

y = - e^{- t - c_{1}} + g

y^{^{'}} = (4 x + 7) (5 y + 4)

x^{^{'}} = x^{2} (t)

\frac{d v}{d x} + xv = 0

\frac{d v}{d t} v = (2^{\frac{5}{2}}) t^{\frac{3}{2}} + 3

\frac{d y}{d x} (sin (π) x + cos (π) y)^{2} = 2