(dx)/(dt)=x+c

Lösung

\frac{d x}{d t} = x + c

x = e^{t + c_{1}} - c

Schritte zur Lösung

\frac{d x}{d t} = x + c

Solve separable ODE:

x = e^{t + c_{1}} - c

x = e^{t + c_{1}} - c

\frac{d V}{d t} = 20 - 0.2 V

\frac{d y}{d x} + 7 y = y^{2} + 12

6 y^{^{'}} - 3 e^{2 x} y = 0, y (0) = 4

y^{^{'}} \cdot sin^{2} (x) = cos (x) (1 - 3 y)

x^{3} y d x + 9 d y = 0