x^2+1dx-3ydy=0

Lösung

x^{2} + 1 d x - 3 y d y = 0

y = \frac{2 x ^{3} + 6 x - c _{1}}{3}, y = - \frac{2 x ^{3} + 6 x - c _{1}}{3}

Schritte zur Lösung

x^{2} + 1 d x - 3 y d y = 0

Solve separable ODE:

y = \frac{2 x ^{3} + 6 x - c _{1}}{3}, y = - \frac{2 x ^{3} + 6 x - c _{1}}{3}

y = \frac{2 x ^{3} + 6 x - c _{1}}{3}, y = - \frac{2 x ^{3} + 6 x - c _{1}}{3}

x^{^{'}} = x^{2} t

y \cdot d x = (- 1 + x) d y

e^{- 2 y} \frac{d y}{d x} = x - 2

\frac{d x}{d y} = e^{x}

3 e^{- 2 y} x^{2} + 8 x e^{- 2 y} = \frac{d y}{d x}