(dy}{dt}=\frac{16t^3)/y

Lösung

\frac{d y}{d t} = \frac{16 t ^{3}}{y}

y = 8 t^{4} + c_{1}, y = - 8 t^{4} + c_{1}

Schritte zur Lösung

\frac{d y}{d t} = \frac{16 t ^{3}}{y}

Solve separable ODE:

y = 8 t^{4} + c_{1}, y = - 8 t^{4} + c_{1}

y = 8 t^{4} + c_{1}, y = - 8 t^{4} + c_{1}

f^{^{'}} (x) + a \cdot f (x) = a \cdot b

y^{^{'}} + 2 y + 6 = 0

\frac{d y}{d x} = y^{2} - 2 y + 1

\frac{d y}{d x} = \frac{4 x}{y - 1}

\frac{d y}{d x} = cos (x) tan (y)