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Beliebt Rechnen >

2y^'=y^3cos(x),y(0)=(1-sin(x))^{-1/2}

Lösung

2 y^{^{'}} = y^{3} cos (x), y (0) = (1 - sin (x))^{- \frac{1}{2}}

Lösung

y = - \frac{1}{sin ( x ) + c _{1}}, y = - - \frac{1}{sin ( x ) + c _{1}}

Schritte zur Lösung

2 y^{'} (x) = y^{3} cos (x)

Solve separable ODE:

y = - \frac{1}{sin ( x ) + c _{1}}, y = - - \frac{1}{sin ( x ) + c _{1}}

y = - \frac{1}{sin ( x ) + c _{1}}, y = - - \frac{1}{sin ( x ) + c _{1}}

Graph

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