(1-y)y^'=x^2

Lösung

(1 - y) y^{^{'}} = x^{2}

y = - \frac{- 6 + 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}, y = - \frac{- 6 - 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}

Schritte zur Lösung

(1 - y) y^{'} (x) = x^{2}

Solve separable ODE:

y = - \frac{- 6 + 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}, y = - \frac{- 6 - 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}

y = - \frac{- 6 + 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}, y = - \frac{- 6 - 36 + 12 ( - c _{1} - 2 x ^{3} )}{6}

(p - 1) y^{^{'}} (p) + 3 y (p) = 0

y^{^{'}} - y - 1 = 0

y^{^{'}} = \frac{- x - x y}{y + x y}

x y y^{^{'}} = ln (x)

\frac{d y}{d t} - 3 y = 0