x^'=-5x^2

Lösung

x^{^{'}} = - 5 x^{2}

x = - \frac{1}{- 5 t + c _{1}}

Schritte zur Lösung

x^{'} (t) = - 5 x^{2}

Solve separable ODE:

x = - \frac{1}{- 5 t + c _{1}}

x = - \frac{1}{- 5 t + c _{1}}

y = e^{- x} \cdot sin (2 x) \cdot \frac{d y}{d x}

y^{^{'}} = 0.00001665 y - 0.8999

(40 x - 24) d x + (87 y + 33) d y = 0

u^{^{'}} = 5 - 0.5 H (t)

f^{^{'}} (x) f (x) = x^{2} + 10 x - 5