y^'=xy+(4x)/y ,y(0)=1

Lösung

y^{^{'}} = x y + \frac{4 x}{y}, y (0) = 1

y = 5 e^{x^{2}} - 4

Schritte zur Lösung

y^{'} (x) = x y + \frac{4 x}{y}

Solve separable ODE:

y = 5 e^{x^{2}} - 4

y = 5 e^{x^{2}} - 4

\frac{d x}{d t} = x^{2} t

(x^{2} + 1) y + 2 x y^{^{'}} + (e^{x}) x y = 0

7 t y^{^{'}} + y = 0

x y^{^{'}} \cdot y = x^{2} sin (x)

\frac{d v}{d t} = - 0.004 v^{2}