y^'=(4x+9)(2y+5)

Lösung

y^{^{'}} = (4 x + 9) (2 y + 5)

y = \frac{e ^{4 x^{2} + 18 x + c_{1}}}{2} - \frac{5}{2}

Schritte zur Lösung

y^{'} (x) = (4 x + 9) (2 y + 5)

Solve separable ODE:

y = \frac{e ^{4 x^{2} + 18 x + c_{1}}}{2} - \frac{5}{2}

y = \frac{e ^{4 x^{2} + 18 x + c_{1}}}{2} - \frac{5}{2}

\frac{d y}{d x} + 2 x = 2 x

y^{^{'}} = \frac{( x ^{2} y ^{2} )}{8} + y^{2}

\frac{d y}{d x} 6 x^{3} y + 2 y = 0

y^{^{'}} = 3 - 5 y

\frac{d y}{d x} = 0.2 \cdot + y + 200