y^'=((2-e^x)/(3+2y))

Lösung

y^{^{'}} = (\frac{2 - e ^{x}}{3 + 2 y})

y = \frac{- 3 + 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}, y = \frac{- 3 - 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}

Schritte zur Lösung

y^{'} (x) = (\frac{2 - e ^{x}}{3 + 2 y})

Solve separable ODE:

y = \frac{- 3 + 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}, y = \frac{- 3 - 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}

y = \frac{- 3 + 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}, y = \frac{- 3 - 9 - 4 ( - c _{1} + e ^{x} - 2 x )}{2}

6 x - 8 y x^{2} + 1 y^{^{'}} = 0

y^{^{'}} + y = x y

1000 y^{^{'}} = 5000 - 100 y

y^{^{'}} = 5 e^{(x - y)}

a y - b t y^{^{'}} = 0