What is the solution for y^{''}-y^'-2y=2x+2 ?

The solution for y^{''}-y^'-2y=2x+2 is y=c_{1}e^{2x}+c_{2}e^{-x}-x-1/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}-y^'-2y=2x+2

y^{^{''}} - y^{^{'}} - 2 y = 2 x + 2

y = c_{1} e^{2 x} + c_{2} e^{- x} - x - \frac{1}{2}

Solution steps

y^{''} (x) - y^{'} (x) - 2 y = 2 x + 2

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} e^{- x} - x - \frac{1}{2}

y = c_{1} e^{2 x} + c_{2} e^{- x} - x - \frac{1}{2}

y^{^{''}} + 10 y^{^{'}} + 9 y = 6 cos (3 t + 1.5708) H (t)

\frac{d ^{2} y}{d x ^{2}} + 4 y = tan (2 x)

y^{^{''''}} + 2 y^{^{''}} + 1 = 0

y^{^{''}} - 2 y^{^{'}} + y = x^{2} + 1

y^{^{''}} - 2 y^{^{'}} + y = \frac{3 e ^{t}}{1 + t ^{2}}

What is the solution for y^{''}-y^'-2y=2x+2 ?
The solution for y^{''}-y^'-2y=2x+2 is y=c_{1}e^{2x}+c_{2}e^{-x}-x-1/2