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tangent f(x)=(x^3+1)(x^2-2),\at x=2

解答

切线

f (x) = (x^{3} + 1) (x^{2} - 2), at x = 2

解答

y = 60 x - 102

求解步骤

找到切点:

(2, 18)

计算

f (x) = (x^{3} + 1) (x^{2} - 2)

的斜率:

\frac{df ( x )}{d x} = 5 x^{4} - 6 x^{2} + 2 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 60

找到斜率 m=

60

且穿过

(2, 18)

的直线:

y = 60 x - 102

y = 60 x - 102

作图

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