y^{''}-y=x-1

Lösung

y^{^{''}} - y = x - 1

y = c_{1} e^{x} + c_{2} e^{- x} - x + 1

Schritte zur Lösung

y^{''} (x) - y = x - 1

Solve linear ODE:

y = c_{1} e^{x} + c_{2} e^{- x} - x + 1

y = c_{1} e^{x} + c_{2} e^{- x} - x + 1

y^{^{''}} + 4 y = t^{2} + 8 e^{t}, y (0) = 0, y^{^{'}} (0) = 7

y^{^{''}} - 4 y = e^{x} cos (x), y (0) = 0.9, y^{^{'}} (0) = - 1.5

\frac{d ^{2} y}{d x ^{2}} + y = 3 sin (2 x)

y^{^{''}} - 4 y = e^{x} cos (x), y (0) = 0.9, y^{^{'}} (0) = - 1.1

y^{^{''}} - 4 y = e^{- 3 x} sin (e^{- x})