derivative of \sqrt[7]{x^3}

Lösung

\frac{d}{d x} (7 x^{3})

\frac{3}{7 x ^{\frac{4}{7}}}

Schritte zur Lösung

\frac{d}{d x} (7 x^{3})

Wende die Kettenregel an:

\frac{1}{7 ( x ^{3} ) ^{\frac{6}{7}}} \frac{d}{d x} (x^{3})

= \frac{1}{7 ( x ^{3} ) ^{\frac{6}{7}}} \frac{d}{d x} (x^{3})

\frac{d}{d x} (x^{3}) = 3 x^{2}

= \frac{1}{7 ( x ^{3} ) ^{\frac{6}{7}}} \cdot 3 x^{2}

Vereinfache

\frac{1}{7 ( x ^{3} ) ^{\frac{6}{7}}} \cdot 3 x^{2} : \frac{3}{7 x ^{\frac{4}{7}}}

= \frac{3}{7 x ^{\frac{4}{7}}}

n = 1 \sum \infty \frac{8 n}{- 2 n + 9}

d er i v a t i v e f (x) = 9 π x^{2}

\frac{d}{d x} ((x^{2} + x^{3}) e^{- \frac{1}{x}})

\int_{0}^{π} 2 sin (x) + sin (2 x) d x

\int csc (π x) cos (π x) d x