integral of (2x+4)

Lösung

\int (2 x + 4) d x

x^{2} + 4 x + C

Schritte zur Lösung

\int 2 x + 4 d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 2 x d x + \int 4 d x

\int 2 x d x = x^{2}

\int 4 d x = 4 x

= x^{2} + 4 x

Füge eine Konstante zur Lösung hinzu

= x^{2} + 4 x + C

d er i v a t i v e ln (7 x)

t an g e n t f (x) = lo g_{5} (2 x^{2} + 7), at x = 3

\frac{d}{d x} ((\frac{2 x + 1}{e + 1})^{e})

\int_{0}^{5} ∣ x - 2 ∣ d x

\int_{0}^{9} \frac{1}{( x - 1 ) ^{\frac{1}{3}}} d x