laplacetransform-5y

Lösung

laplace transformation

- 5 y

- \frac{5}{s ^{2}}

Schritte zur Lösung

L {- 5 y}

Verwende die konstante Multiplikationseigenschaft der Laplace-Transformation:

For function

f (t)

and constant

a : L {a \cdot f (t)} = a \cdot L {f (t)}

= - 5 L {y}

L {y} : \frac{1}{s ^{2}}

= - 5 \cdot \frac{1}{s ^{2}}

Fasse

- 5 \frac{1}{s ^{2}}

zusammen:

- \frac{5}{s ^{2}}

= - \frac{5}{s ^{2}}

a re a 3 (x^{3} - x), 0

\frac{d}{d x} (30)

\frac{d y}{d x} = \frac{( ( 1 + y ) ^{2} )}{( 1 + x ) ^{3}}

\int e^{- 2 x} cos (e^{- x}) d x

\frac{\partial}{\partial x} (ln (x + \frac{y}{2 x}))