What is (\partial}{\partial t}(\frac{s-r)/t) ?

The answer to (\partial}{\partial t}(\frac{s-r)/t) is -(s-r)/(t^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial}{\partial t}(\frac{s-r)/t)

\frac{\partial}{\partial t} (\frac{s - r}{t})

- \frac{s - r}{t ^{2}}

Solution steps

\frac{\partial}{\partial t} (\frac{s - r}{t})

Treat

s, r

as constants

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= (s - r) \frac{\partial}{\partial t} (\frac{1}{t})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= (s - r) \frac{\partial}{\partial t} (t^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= (s - r) (- 1 \cdot t^{- 1 - 1})

Simplify

(s - r) (- 1 \cdot t^{- 1 - 1}) : - \frac{s - r}{t ^{2}}

= - \frac{s - r}{t ^{2}}

(e^{2 t})^{^{'}}

\int sin (θ) cos (θ) d θ

\int_{- 2}^{3} \frac{1}{x ^{4}} d x

2 y^{^{''}} + 5 y^{^{'}} + 3 y = 0

\int \frac{1}{2 x + 1} d x

What is (\partial}{\partial t}(\frac{s-r)/t) ?
The answer to (\partial}{\partial t}(\frac{s-r)/t) is -(s-r)/(t^2)