2y^{''}+5y^'+3y=0

Lösung

2 y^{^{''}} + 5 y^{^{'}} + 3 y = 0

y = c_{1} e^{- t} + c_{2} e^{- \frac{3 t}{2}}

Schritte zur Lösung

2 y^{''} (t) + 5 y^{'} (t) + 3 y = 0

Solve linear ODE:

y = c_{1} e^{- t} + c_{2} e^{- \frac{3 t}{2}}

y = c_{1} e^{- t} + c_{2} e^{- \frac{3 t}{2}}

\int \frac{1}{2 x + 1} d x

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