What is the derivative of f(x)=(16)/x ?

The derivative of f(x)=(16)/x is -(16)/(x^2)

What is the first derivative of f(x)=(16)/x ?

The first derivative of f(x)=(16)/x is -(16)/(x^2)

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derivative of

f (x) = \frac{16}{x}

- \frac{16}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{16}{x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 16 \frac{d}{d x} (\frac{1}{x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 16 \frac{d}{d x} (x^{- 1})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 16 (- 1 \cdot x^{- 1 - 1})

Simplify

16 (- 1 \cdot x^{- 1 - 1}) : - \frac{16}{x ^{2}}

= - \frac{16}{x ^{2}}

x \to π lim (cot (x))

a re a y = ∣ x ∣ + ∣ x - 1 ∣, x = - 1, x = 2

\frac{\partial}{\partial x} (arctan (x) y)

a re a (x - 1)^{3}, x - 1

\int - x - 1 d x

What is the derivative of f(x)=(16)/x ?
The derivative of f(x)=(16)/x is -(16)/(x^2)
What is the first derivative of f(x)=(16)/x ?
The first derivative of f(x)=(16)/x is -(16)/(x^2)