integral from 0 to 3 of |3x-1|

Lösung

\int_{0}^{3} ∣ 3 x - 1 ∣ d x

\frac{65}{6}

Dezimale

10.83333 \dots

Schritte zur Lösung

\int_{0}^{3} ∣ 3 x - 1 ∣ d x

Entferne die Extremwerte

= \int_{0}^{\frac{1}{3}} - 3 x + 1 d x + \int_{\frac{1}{3}}^{3} 3 x - 1 d x

\int_{0}^{\frac{1}{3}} - 3 x + 1 d x = \frac{1}{6}

\int_{\frac{1}{3}}^{3} 3 x - 1 d x = \frac{32}{3}

= \frac{1}{6} + \frac{32}{3}

Vereinfache

\frac{1}{6} + \frac{32}{3} : \frac{65}{6}

= \frac{65}{6}

\frac{\partial}{\partial x} (x^{2} + x y + 3 y)

\int (z + 1) e^{2 z} d z

\int x (x^{2} - 3)^{3} d x

\frac{\partial}{\partial x} (a^{- x})

\frac{d}{d x} (\frac{x}{3 x ^{2} + 4})