What is the d/(dt)(tan(3t)) ?

The d/(dt)(tan(3t)) is sec^2(3t)*3

What is the first d/(dt)(tan(3t)) ?

The first d/(dt)(tan(3t)) is sec^2(3t)*3

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\frac{d}{d t} (tan (3 t))

sec^{2} (3 t) \cdot 3

Solution steps

\frac{d}{d t} (tan (3 t))

Apply the chain rule:

sec^{2} (3 t) \frac{d}{d t} (3 t)

= sec^{2} (3 t) \frac{d}{d t} (3 t)

\frac{d}{d t} (3 t) = 3

= sec^{2} (3 t) \cdot 3

n = 1 \sum \infty \frac{2}{3 ^{2 n}}

y^{^{'''}} + 4 y^{^{'}} = sec (2 x)

x \to 0 lim (3 π)

f (θ) = 4 cos (θ)

\int 4 x e^{\frac{2}{3} x} d x